Comments on: Shock Testing: Long Duration Half Sine Shock https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/ Product Reliability & Vibration Testing Since 1982 Thu, 17 Sep 2020 10:18:51 +0000 hourly 1 https://wordpress.org/?v=5.6.13 By: WZ https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-64243 Thu, 17 Sep 2020 10:18:51 +0000 https://www.desolutions.com/blog/?p=2229#comment-64243 Totally agree with Stella. You did a lot of very cool studies with description in detail.
Great thanks for sharing.

]]> By: Stella https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-59189 Sat, 01 Jun 2019 14:55:43 +0000 https://www.desolutions.com/blog/?p=2229#comment-59189 Admiring the hard work you put into your blog and in depth information you offer.
It’s awesome to come across a blog every once in a while that isn’t the
same out of date rehashed material. Great read! I’ve bookmarked
your site and I’m including your RSS feeds
to my Google account.

]]> By: DES https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-59022 Thu, 09 May 2019 21:07:08 +0000 https://www.desolutions.com/blog/?p=2229#comment-59022 In reply to Ron Garrett.

Not necessarily. For a half-sine pulse,the relation of the time duration of the pulse to the frequency is 1/2T = f, where
T = time duration, seconds
f = frequency, Hz

The frequency of a 6ms shock is different than for a 10ms and so on. So it depends how your product responds to the fundamental shock frequency.

]]> By: Ron Garrett https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-59020 Thu, 09 May 2019 18:44:33 +0000 https://www.desolutions.com/blog/?p=2229#comment-59020 Which is more difficult on the product being tested – A 6 ms duration shock or a 10 ms shock. If the duration is longer does that make it easier on the unit being tested?

]]> By: Lee https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-58520 Thu, 14 Mar 2019 21:48:35 +0000 https://www.desolutions.com/blog/?p=2229#comment-58520 In reply to Jack.

Hello, I am sorry. I figured it out. the equation is actually a=sin2Pifdt. So then the integral of that is the velocity change. Thank you very much.

]]> By: Lee https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-58518 Thu, 14 Mar 2019 21:19:29 +0000 https://www.desolutions.com/blog/?p=2229#comment-58518 In reply to Jack.

Hello DES, Thank you for this. I am not understanding the part of (2/3.14). I know the dV=a*dt. The velocity change is from 0 to max and max to 0 so it is 2. But how did you get the 3.14 to divide? I am sorry for my slow understanding.

]]> By: Jack https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-56102 Tue, 22 May 2018 20:55:56 +0000 https://www.desolutions.com/blog/?p=2229#comment-56102 In reply to DES.

Hi DES, thanks a lot for the quick response. I see how you got that

]]> By: DES https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-56101 Tue, 22 May 2018 20:26:47 +0000 https://www.desolutions.com/blog/?p=2229#comment-56101 In reply to Jack.

The velocity change for a half sine shock is dV = (2/3.14) x 35G x (386 (in/s^2)/G) x (.050 second duration) = 430 in/sec

]]> By: Jack https://www.desolutions.com/blog/2015/05/shock-testing-long-duration-half-sine-shock/#comment-56099 Tue, 22 May 2018 17:49:05 +0000 https://www.desolutions.com/blog/?p=2229#comment-56099 In your example you noted that the required velocity change for a 35G, 50 millisecond duration half sine shock is 430 inches per second. How did you determine this?

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